Use jQuery to select multiple elements with .eq()

Question

I want to select a subset of tds from a table.

I know before hand what the indexes are, but they are effectively random (not odd or even indexes, etc).

For i

Answer 1

$('table td').filter(':eq(' + indexesToSelect.join('), :eq(') + ')')

Answer 2

I'd do it with .filter() and $.inArray():

var elements = $("table td").filter(function(i) {
    return $.inArray(i, indexesToSelect) > -1;
});

Another [more ugly] way is mapping to a selector:

var elements = $($.map(indexesToSelect, function(i) {
    return "td:eq(" + i + ")";
}).join(","), "table");

Answer 3

I wrapped VisioN's filter method into a jQuery plugin:

$.fn.eqAnyOf = function (arrayOfIndexes) {
    return this.filter(function(i) {
        return $.inArray(i, arrayOfIndexes) > -1;
    });
};

So now usage is nice and clean:

var $tds = $('table td').eqAnyOf([1, 5, 9]);

Answer 4

try this

   $('table td:eq(0), table td:eq(5), table td:eq(9)')