What does “with” do in JavaScript?

Question

I saw JavaScript code which begins with with. That\'s a bit confusing. What does it do and how can it be used correctly?

with (sObj) return opti         


        

Answer 1

In that with block you dont have to type:

sObj.options[selectedIndex].value

but you can just use:

options[selectedIndex].value

Answer 2

I would recommend NOT using this because of performance issues, but what the above means is:

for the object sObj (here presumably a select element), all children and properties referenced on this one (or between following curly braces) treat that as their parent scope.

Answer 3

Your example could be rewritten as...

return sObj.options[selectedIndex].value;

...as the 'with' statement places all related statements in the scope of the supplied object. In this case, it's pretty pointless but, if you were doing lots of operations on 'sObj', then it saves a lot of typing.

Totally ficticious example..

with (sObj) 
{
   if(options[selectedIndex].value < 10){
       options[selectedIndex].value++;
       total+ = options[selectedIndex].value;
   }
}

But, having said that, it's often the case that saving typing can be achieved in better ways.

Answer 4

It brings pain and suffering among you and others

Answer 5

the with statement is pure syntactical sugar, but it also can cause some nasty bugs.

See with Statement Considered Harmful for clarification:

If you can't read a program and be confident that you know what it is going to do, you can’t have confidence that it is going to work correctly. For this reason, the with statement should be avoided.

Answer 6

It adds to the scope of the statements contained in the block:

return sObj.options[selectedIndex].value;

can become:

with (sObj)
    return options[selectedIndex].value;

In your case, it doens't do a whole lot...but consider the following:

var a, x, y;
var r = 10;
a = Math.PI * r * r;
x = r * Math.cos(PI);
y = r * Math.sin(PI /2);

Becomes:

var a, x, y;
var r = 10;
with (Math) {
  a = PI * r * r;
  x = r * cos(PI);
  y = r * sin(PI / 2);
}

...saves a couple of keystrokes. The Mozilla documentation actually does a pretty good job of explaining things in a little more detail (along with pros and cons of using it):

with - Mozilla Developer Center