How to remove an element of a given value from an array in Swift

Question

I want to remove all elements of value x from an array that contains x, y and z elements

let arr = [\'a\', \'b\', \'c\', \'b\']

How can I r

Answer 1

A general approach is to exploit first class procedures. (However, this approach is much more powerful than what is required for your question.) To illustrate, say you want to avoid "Justin" repeatedly in many collections.

let avoidJustin = notEqualTester ("Justin")

let arrayOfUsers = // ...

arrayOfUsers.filter (avoidJustin)

let arrayOfFriends = // ...

arrayOfFriends.filter (avoidJustin)

With this, you avoid repeatedly creating a closure each time you want to avoid Justin. Here is notEqualTester which, given a that, returns a function of this that returns this != that.

func notEqualTester<T: Equatable> (that:T) -> ((this:T) -> Bool) {
  return { (this:T) -> Bool in return this != that }
}

The returned closure for this captures the value for that - which can be useful when that is no longer available.