Is it possible to easily round a figure up to the nearest 100 (or 1000, 500, 200 etc.) in SQL Server?
So:
720 -> 800
790 -> 800
1401 -> 1500
One option would be to use the CEILING() function like this:
SELECT CEILING(@value/100.0) * 100
You may need to convert your value to a decimal first depending on its type.
For rounding Up to the nearest thousand, Please try the following:-
select round(YourValue, -3)
Cheers!!!!!
This will work for the values with decimal also.
select floor((ceiling (@value) + 99) / 100) * 100;
In addition to Gray's answer, I'd use the following inline function:
CREATE FUNCTION dbo.udf_RoundNearest
(
@Number bigint,
@RoundNearest bigint,
@Direction int
)
RETURNS TABLE AS
RETURN
SELECT CASE WHEN @RoundNearest>=@Number THEN @Number
ELSE
(
(@Number + CASE
WHEN @Direction = 0 --Round Down
THEN 0
ELSE CASE WHEN @Number % @RoundNearest = 0 THEN 0 ELSE @RoundNearest END
END) / @RoundNearest) * @RoundNearest
END Number
Parameter Definition:
using the function:
SELECT * FROM dbo.udf_RoundNearest (1965,100,1) --> 2000
SELECT * FROM dbo.udf_RoundNearest (1359,100,0) --> 1300
SELECT * FROM dbo.udf_RoundNearest (1999,10,0) --1990
SELECT * FROM dbo.udf_RoundNearest (80,100,0) --> 80 (if the @number parameter is less or equal the @RoundNearest parameter the result will be the @number itself
it can also be used as apply it versus a table such as:
;with tmp (Value) as
(select 1236 union all select 6584 union all select 9999)
select t.*, fn.Number
from tmp t
cross apply dbo.udf_RoundNearest (Value,100,0) fn
/*Result Set
Value Number
1236 1200
6584 6500
9999 9900*/
A generic solution - Use MOD to find the last 100th place and then add 100 to the result.
select (720 - MOD(720,100)) + 100 from dual;
If you need the next 80th place, just replace any "100" with "80".
This worked fine for me.
Round(@value/100, 0) * 100