Ruby Array find_first object?

Question

Am I missing something in the Array documentation? I have an array which contains up to one object satisfying a certain criterion. I\'d like to efficiently find that objec

Answer 1

Guess you just missed the find method in the docs:

my_array.find {|e| e.satisfies_condition? }

Answer 2

Do you need the object itself or do you just need to know if there is an object that satisfies. If the former then yes: use find:

found_object = my_array.find { |e| e.satisfies_condition? }

otherwise you can use any?

found_it = my_array.any?  { |e| e.satisfies_condition? }

The latter will bail with "true" when it finds one that satisfies the condition. The former will do the same, but return the object.

Answer 3

use array detect method if you wanted to return first value where block returns true

[1,2,3,11,34].detect(&:even?) #=> 2

OR

[1,2,3,11,34].detect{|i| i.even?} #=> 2

If you wanted to return all values where block returns true then use select

[1,2,3,11,34].select(&:even?)  #=> [2, 34]

Answer 4

Either I don't understand your question, or Enumerable#find is the thing you were looking for.