Reading multiple lines of input with scanf

Question

Writing a program for class, restricted to only scanf method. Program receives can receive any number of lines as input. Trouble with receiving input of multiple lines with

Answer 1

Try this piece of code.. It works as desired on a GCC compiler with C99 standards..

#include<stdio.h>
int main()
{
int s[100];
printf("Enter multiple line strings\n");
scanf("%[^\r]s",s);
printf("Enterd String is\n");
printf("%s\n",s);
return 0;
}

Answer 2

try this code and use tab key as delimeter

#include <stdio.h>
int main(){
    char s[100];
    scanf("%[^\t]",s);
    printf("%s",s);

    return 0;
}

Answer 3

I think what you want is something like this (if you're really limited only to scanf):

#include <stdio.h>
int main(){
    char s[100];
    while(scanf("%[^\n]%*c",s)==1){
        printf("%s\n",s);
    }
    return 0;
}

The %*c is basically going to suppress the last character of input.

From man scanf

An optional '*' assignment-suppression character: 
scanf() reads input as directed by the conversion specification, 
but discards the input.  No corresponding pointer argument is 
required, and this specification is not included in the count of  
successful assignments returned by scanf().

[ Edit: removed misleading answer as per Chris Dodd's bashing :) ]

Answer 4

I'll give you a hint.

You need to repeat the scanf operation until an "EOF" condition is reached.

The way that's usually done is with the

while (!feof(stdin)) {
}

construct.