Get the last 4 characters of output from standard out

Question

I have a script that is running and uses

lspci -s 0a.00.1 

This returns

0a.00.1 usb controller some text device 4dc9


        

Answer 1

Try using grep:

lspci -s 0a.00.1 | grep -o ....$

This will print last 4 characters of every line.

However if you'd like to have last 4 characters of the whole output, use tail -c4 instead.

Answer 2

One more way to approach this is to use <<< notation:

tail -c 5 <<< '0a.00.1 usb controller some text device 4dc9'

Answer 3

Using sed:

lspci -s 0a.00.1 | sed 's/^.*\(.\{4\}\)$/\1/'

Output:

4dc9

Answer 4

I usually use

echo 0a.00.1 usb controller some text device 4dc9 | rev | cut -b1-4 | rev
4dc9

Answer 5

Try this, say if the string is stored in the variable foo.

foo=`lspci -s 0a.00.1` # the foo value should be "0a.00.1 usb controller some text device 4dc9"
echo ${foo:(-4)}  # which should output 4dc9

Answer 6

Do you really want the last four characters? It looks like you want the last "word" on the line:

awk '{ print $NF }'

This will work if the ID is 3 characters, or 5, as well.