How to execute Python inline from a bash shell

Question

Is there a Python argument to execute code from the shell without starting up an interactive interpreter or reading from a file? Something similar to:

perl          


        

Answer 1

A 'heredoc' can be used to directly feed a script into the python interpreter:

python <<HEREDOC
import sys
for p in sys.path:
  print(p)
HEREDOC


/usr/lib64/python36.zip
/usr/lib64/python3.6
/usr/lib64/python3.6/lib-dynload
/home/username/.local/lib/python3.6/site-packages
/usr/local/lib/python3.6/site-packages
/usr/lib64/python3.6/site-packages
/usr/lib/python3.6/site-packages

Answer 2

Another way is to you use bash redirection:

python <<< 'print "Hi"'

And this works also with perl, ruby, and what not.

p.s.

To save quote ' and " for python code, we can build the block with EOF

c=`cat <<EOF
print(122)
EOF`
python -c "$c"

Answer 3

This works:

python -c 'print("Hi")'
Hi

From the manual, man python:

   -c command
          Specify  the command to execute (see next section).  This termi-
          nates the option list (following options are passed as arguments
          to the command).

Answer 4

Another way is to use the e module

eg.

$ python -me 1 + 1
2