Question about vector iterator in template functions

Question

I\'m trying to learn the STL library and I\'m having a weird problem. This code compiles perfectly:

void Show(vector myvec)
{
    vector

        

Answer 1

Some compilers have problems detecting what is a member name and what is a type name, when inside templates. Try writing something like this in the first line of your template function body.

typename vector<T>::iterator it;

Answer 2

You need to say typename vector<T>::iterator it.

On another note, you're passing vectors by value. That means the entire vector gets copied in the function call. void Show(vector<T> const &myvec) and using const_iterator would be wiser.

Answer 3

You need this:

typename vector<T>::iterator it;

This tells the compiler that vector<T>::iterator should be treated as a type, something it can't assume since iterator is dependent on what T is.

Answer 4

Maybe it works using typename vector<T>::iterator it; Your compiler cannot know that there is an inner class iterator.

Answer 5

In the first instance the parameter, although it uses a template, is not a template, it is a fully defined class (vector<int>)

In the latter instance the parameter is a template on type T and thus requires typename