Get file from project folder java

Question

I want to get File from project folder by using \"File class\" , How I can Do that ?

File file=new File(\"x1.txt\");

Answer 1

This sounds like the file is embedded within your application.

You should be using getClass().getResource("/path/to/your/resource.txt"), which returns an URL or getClass().getResourceAsStream("/path/to/your/resource.txt");

If it's not an embedded resource, then you need to know the relative path from your application's execution context to where your file exists

Answer 2

If you are trying to load a file which is not in the same directory as your Java class, you've got to use the runtime directory structure rather than the one which appears at design time.

To find out what the runtime directory structure is, check your {root project dir}/target/classes directory. This directory is accessible via the "." URL.

Based on user4284592's answer, the following worked for me:

ClassLoader cl = getClass().getClassLoader();
File file = new File(cl.getResource("./docs/doc.pdf").getFile());

with the following directory structure:

{root dir}/target/classes/docs/doc.pdf

Here's an explanation, so you don't just blindly copy and paste my code:

• java.lang.ClassLoader is an object that is responsible for loading classes. Every Class object contains a reference to the ClassLoader that defined it and can fetch it with getClassLoader() method.
• ClassLoader's getResource method finds the resource with the given name. A resource is some data that can be accessed by class code in a way that is independent of the location of the code.

Answer 3

in javaFx 8

javafx.scene.image.Image img = new javafx.scene.image.Image("/myPic.jpg", true);

URL url = new URL(img.impl_getUrl());

Answer 4

Just did a quick google search and found that

System.getProperty("user.dir");

returns the current working directory as String. So to get a File out of this, just use

File projectDir = new File(System.getProperty("user.dir"));

Answer 5

Given a file application.yaml in test/resources

ll src/test/resources/
total 6
drwxrwx--- 1 root vboxsf 4096 Oct  6 12:23 ./
drwxrwx--- 1 root vboxsf    0 Sep 29 17:05 ../
-rwxrwx--- 1 root vboxsf  142 Sep 22 23:59 application.properties*
-rwxrwx--- 1 root vboxsf   78 Oct  6 12:23 application.yaml*
-rwxrwx--- 1 root vboxsf    0 Sep 22 17:31 db.properties*
-rwxrwx--- 1 root vboxsf  618 Sep 22 23:54 log4j2.json*

From the test context, I can get the file with

String file = getClass().getClassLoader().getResource("application.yaml").getPath(); 

which will actually point to the file in test-classes

ll target/test-classes/
total 10
drwxrwx--- 1 root vboxsf 4096 Oct  6 18:49 ./
drwxrwx--- 1 root vboxsf 4096 Oct  6 18:32 ../
-rwxrwx--- 1 root vboxsf  142 Oct  6 17:35 application.properties*
-rwxrwx--- 1 root vboxsf   78 Oct  6 17:35 application.yaml*
drwxrwx--- 1 root vboxsf    0 Oct  6 18:50 com/
-rwxrwx--- 1 root vboxsf    0 Oct  6 17:35 db.properties*
-rwxrwx--- 1 root vboxsf  618 Oct  6 17:35 log4j2.json*

Answer 6

Well, there are many different ways to get a file in Java, but that's the general gist.

Don't forget that you'll need to wrap that up inside a try {} catch (Exception e){} at the very least, because File is part of java.io which means it must have try-catch block.

Not to step on Ericson's question, but if you are using actual packages, you'll have issues with locations of files, unless you explicitly use it's location. Relative pathing gets messed up with Packages.

ie,

src/
    main.java
    x.txt

In this example, using File f = new File("x.txt"); inside of main.java will throw a file-not-found exception.

However, using File f = new File("src/x.txt"); will work.

Hope that helps!