SQL - select distinct only on one column [duplicate]

Answer 1

You will use the following query:

SELECT * FROM [table] GROUP BY NUMBER;

Where [table] is the name of the table.

This provides a unique listing for the NUMBER column however the other columns may be meaningless depending on the vendor implementation; which is to say they may not together correspond to a specific row or rows.

Answer 2

Since you don't care, I chose the max ID for each number.

select tbl.* from tbl
inner join (
select max(id) as maxID, number from tbl group by number) maxID
on maxID.maxID = tbl.id

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Query Explanation

 select 
    tbl.*  -- give me all the data from the base table (tbl) 
 from 
    tbl    
    inner join (  -- only return rows in tbl which match this subquery
        select 
            max(id) as maxID -- MAX (ie distinct) ID per GROUP BY below
        from 
            tbl 
        group by 
            NUMBER            -- how to group rows for the MAX aggregation
    ) maxID
        on maxID.maxID = tbl.id -- join condition ie only return rows in tbl 
                                -- whose ID is also a MAX ID for a given NUMBER

Answer 3

A very typical approach to this type of problem is to use row_number():

select t.*
from (select t.*,
             row_number() over (partition by number order by id) as seqnum
      from t
     ) t
where seqnum = 1;

This is more generalizable than using a comparison to the minimum id. For instance, you can get a random row by using order by newid(). You can select 2 rows by using where seqnum <= 2.