RegEx to find two or more consecutive chars

Question

I need to determine if a string contains two or more consecutive alpha chars. Two or more [a-zA-Z] side by side. Example:

\"ab\" -> valid
\"a         


        

Answer 1

This should do the trick:

[a-zA-Z]{2,}

Answer 2

Personnaly (as a nooby) I've used:

[0-9][0-9]+.

But the one from Simon, is way better ! =D

Answer 3

I'm pretty sure you can just use [A-z] instead of the [a-zA-Z] to get small and upper case alpha chars http://www.w3schools.com/jsref/jsref_obj_regexp.asp

Answer 4

[a-zA-Z]{2,} does not work for two or more identical consecutive characters. To do that, you should capture any character and then repeat the capture like this:

(.)\1

The parenthesis captures the . which represents any character and \1 is the result of the capture - basically looking for a consecutive repeat of that character. If you wish to be specific on what characters you wish to find are identical consecutive, just replace the "any character" with a character class...

([a-zA-Z])\1

Finds a consecutive repeating lower or upper case letter. Matches on "abbc123" and not "abc1223". To allow for a space between them (i.e. a ab), then include an optional space in the regex between the captured character and the repeat...

([a-z]A-Z])\s?\1