How do I call a super class method

Question

I have two classes A, and B. Class B overrides the foo method of class A. Class B has a b

Answer 1

Based on @Sony's answer.

In case when you want to call the method method on some my_object and it's already overriden somewhere several classes higher (like for the Net::HTTPRequest#method), instead of doing .superclass.superclass.superclass use the:

Object.instance_method(:method).bind(my_object)

Like this:

p Object.instance_method(:method).bind(request).call(:basic_auth).source_location

Answer 2

In this particular case you can just alias :bar :foo before def foo in class B to rename the old foo to bar, but of course you can alias to any name you like and call it from that. This question has some alternative ways to do it further down the inheritance tree.

Answer 3

You can alias old_foo foo before redefining it to keep the old implementation around under a new name. (Technically it is possible to take a superclass's implementation and bind it to an instance of a subclass, but it's hacky, not at all idiomatic and probably pretty slow in most implementation to boot.)

Answer 4

You can do:

 def bar
   self.class.superclass.instance_method(:foo).bind(self).call
 end

Answer 5

In Ruby 2.2, you can use Method#super_method now

For example:

class B < A
  def foo
    super + " world"
  end

  def bar
    method(:foo).super_method.call
  end
end

Ref: https://bugs.ruby-lang.org/issues/9781#change-48164 and https://www.ruby-forum.com/topic/5356938