Pseudo-form in Django admin that generates a json object on save

Question

I have a model with a field for a json object. This object is used on the site to control some css variables, among other things.

Right now in the admin, I have a t

Answer 1

It's looks simple like this:

#Creating custom form 
class MyCoolForm(forms.ModelForm):
    class Meta: 
        model = MyModel
        exclude = ('field_that_stores_json', ) 
    #field_that_shows_json1 = forms.CharField() 
    #field_that_shows_jsons = forms.CharField() 

    def __init__(self, *args, **kwargs):
        #Deserizlize field that stores json here

    def save(self, *args, **kwargs):
        #Serialize fields that shows json here

After all, just set this form as a form for admin.

P.S.: Also you can write your own widget for form, that transforms json object into fields on js level and has textarea underneath.

Answer 2

Try using YAML as the format for user input, and then deserialize the object and serialize it back to json in the back end. Django already has serializers for that.

Answer 3

Basically it sounds like you want a custom widget for your text field. The snippet on this page gives an example on how to render json key-value pairs. Even if it doesn't suit your needs entirely, especially as your nested json adds some complexity, it perhaps can give you some ideas.

As for the pure storage and retrieval of json objects into Python dicts, a few reusable JSONField implementations exist, like this one. You might want to add it to the mix.

Answer 4

Interesting question! I'd like to see good and elegant solution for it :) But it seems to me, that django-admin is not suitable for your task. I'd try to play with Forms. Smth like this:

class HmmForm(forms.Form):
    name = forms.CharField(max_length = 128)
    user_id = forms.IntegerField()
    height = forms.IntegerField()
    weight = forms.IntegerField()


def test(request, pk):
    form = HmmForm()
    if pk > 0:
        hmm = Hmm.objects.get(pk = pk)
        form = HmmForm( initial = {"name": hmm.name} )
    return render_to_response("test/test.html", {"form": form})

And then simple render form in template, as you wish:

{{ form.as_table }} or {{ form.as_p }}

Answer 5

I had similar task. I resolved it by creating Django form widget. You can try it for yours applications django-SplitJSONWidget-form

Answer 6

django-submodel may help you, although it cannot represent layered key-value now.

It's a pity to miss such HUGE bounty =p