python try:except:finally

Question

# Open new file to write
file = None
try:
    file = open(filePath, \'w\')
except IOError:
    msg = (\"Unable to create file on disk.\")
    file.close()
    return         


        

Answer 1

Here is the most direct solution to your problem. I use the idiom of checking for file_obj != None in the finally block.

By the way, you should be aware that file is a Python class name, so you should choose a different variable name.

file = None
try:
    file = open(filePath, 'w')
except IOError:
    msg = ("Unable to create file on disk.")
    file.close()
    return
finally:
    if file != None:
        file.write("Hello World!")
        file.close()

Answer 2

You can do something like this:

try:
    do_some_stuff()
finally:
    cleanup_stuff()