How to Query model where name contains any word in python list?

Question

Aim to Achieve:

I want all objects where name attribute contains any word from the list.

I have:

list = [\'word1\',\'word2\',\'word3\']
ob_li         


        

Answer 1

obj_list = [obj for obj in data.objects.all() if any(name in obj.name for name in list)]

Edit: Just re-read your question. Don't know if you can do that with filter but you can do it with a list comprehension or generator expression.

Answer 2

You could use Q objects to constuct a query like this:

from django.db.models import Q

ob_list = data.objects.filter(reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))

Edit:

reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))

is a fancy way to write

Q(name__contains=list[0]) | Q(name__contains=list[1]) | ... | Q(name__contains=list[-1])

You could also use an explicit for loop to construct the Q object.

Answer 3

ob_list = data.objects.filter(name__in=my_list)

And BTW, avoid using the variable name "list" (Or any other python standard keyword), lest you get into some weird bugs later.

Update: (I guess your question was updated too, because when I wrote the answer, I didn't see the part where you wrote you need a contains match and not an exact match)

You can do that using the regex search too, avoiding many Q expressions (which end up using that many where "and" clauses in the SQL, possibly dampening the performance), as follows:

data.objects.filter(name__regex=r'(word1|word2|word3)')