How to get device width and height?

Question

In Objective-C we can get device width and height by using following code :

CGRect sizeRect = [UIScreen mainScreen].applicationFrame
float width = sizeRect.         


        

Answer 1

(Swift 3) Keep in mind that most width and height values will be based on device's current orientation. If you want a consistent value that is not based on rotation and offers results as if you were in a portrait-up rotation, give fixedCoordinateSpace a try:

let screenSize = UIScreen.main.fixedCoordinateSpace.bounds

Answer 2

Swift 4.2

let screenBounds = UIScreen.main.bounds
let width = screenBounds.width
let height = screenBounds.height

Answer 3

A UIScreen object defines the properties associated with a hardware-based display. iOS devices have a main screen and zero or more attached screens. Each screen object defines the bounds rectangle for the associated display and other interesting properties

Apple Doc URL :

https://developer.apple.com/reference/uikit/uiwindow/1621597-screen

To get Height/width of ur user's device with swift 3.0

let screenHeight = UIScreen.main.bounds.height
let screenWidth = UIScreen.main.bounds.width

Answer 4

@Houssni 's answer is correct, but since we're talking Swift and this use case will come up often, one could consider extending CGRect similar to this:

extension CGRect {
    var wh: (w: CGFloat, h: CGFloat) {
        return (size.width, size.height)
    }
}

Then you can use it like:

let (width, height) = UIScreen.mainScreen().applicationFrame.wh

Hooray! :)

Answer 5

 static func getDeviceType() -> String
    {
        var strDeviceType = ""
        if UIDevice().userInterfaceIdiom == .phone {
            switch UIScreen.main.nativeBounds.height {
            case 1136:
                strDeviceType = "iPhone 5 or 5S or 5C"
            case 1334:
                strDeviceType = "iPhone 6/6S/7/8"
            case 1920, 2208:
                strDeviceType = "iPhone 6+/6S+/7+/8+"
            case 2436:
                strDeviceType = "iPhone X"
            case 2688:
                strDeviceType = "iPhone Xs Max"
            case 1792:
                strDeviceType = "iPhone Xr"
            default:
                strDeviceType = "unknown"
            }
        }
        return strDeviceType
    }

Answer 6

In Swift 4 I had to use NSScreen.main?.deviceDescription

let deviceDescription = NSScreen.main?.deviceDescription          
let screenSize = deviceDescription![.size]
let screenHeight = (screenSize as! NSSize).height