What does “wget -O” mean?

Question

I have an wget command like this in my shell script:

reponse=\"`wget -O- http:localhost:8080/app/index.html`\"

I don\'t understand the -O-

Answer 1

wget -O teleComData.csv https://s3-api.us-geo.objectstorage.softlayer.net/cf-courses-data/CognitiveClass/ML0101ENv3/labs/teleCust1000t.csv

This command downloads the csv file from the specified url and saves it as teleComData.csv. If you hadn't used the -O flag, it would simply save the file as it is.

Answer 2

Depending on your system you should be able to find reference by typing man wget. The GNU Wget man page says this of the -O|--output-document flag:

If - is used as file, documents will be printed to standard output, disabling link conversion. (Use ./- to print to a file literally named -.)

And continues…

Use of -O is not intended to mean simply "use the name file instead of the one in the URL;" rather, it is analogous to shell redirection: wget -O file http://foo is intended to work like wget -O - http://foo > file; file will be truncated immediately, and all downloaded content will be written there.

It's not uncommon to see combined with -q and written as -q0- or -q0 - followed by a uri. It validates against the POSIX standard so, yeah, I'd say it's a standard thing for shell scripting.

Answer 3

Here's the man page of wget -O:

http://www.gnu.org/software/wget/manual/html_node/Download-Options.html#Download-Options

Here's a few examples:

1. wget with no flag

   wget www.stackoverflow.com
   

   Output:

   A file named as index.html

2. wget with -O flag

   wget -O filename.html www.stackoverflow.com
   

   Output:

   A file named as filename.html

3. wget with -O- flag

   wget -O- www.stackoverflow.com
   

   Output:

   Output to stdout

Answer 4

for the manual of wget: use man wget if you are on Unix platform. Else, try "man page wget" on google.

The -O- stand for "Get as a file and print the result on STDOUT"