How can I get inside parentheses value in a string?

Question

How can I get inside parentheses value in a string?

String str= "United Arab Emirates Dirham (AED)";

I need only AED text.

Answer 1

The below method can split any String inside any bracket like '(. {. [, ), }, ]'.

public String getStringInsideChars(String original, char c){
    this.original=original;
    original = cleaning(original);
    for(int i = 0; i < original.length(); i++){
        if(original.charAt(i) == c){
            String temp = original.substring(i + 1, original.length());
            i = original.length();//end for
            for(int k = temp.length() - 1; k >= 0; k--){
                if(temp.charAt(k) == getReverseBracket(c)){
                    original = temp.substring(0, k);
                    k = -1; // end for
                }
            }
        }
    }
    return original;
}

private char getReverseBracket(char c){
    return c == '(' ? ')' :
           c == '{' ? '}' :
           c == '[' ? ']' :
           c == ')' ? '(' :
           c == '}' ? '{' :
           c == ']' ? '[' : c;
}

public String cleaning(String original) {
    this.original = original;
    return original.replaceAll(String.valueOf('\t'), "").replaceAll(System.getProperty("line.separator"), "");
}

You can use it like below :

getStringInsideChars("{here is your string}", '{')

it will return "here is your string"

Answer 2

i can't get idea how to split inside parentheses. Would you help highly appreciated

When you split you are using a reg-ex, therefore some chars are forbidden.

I think what you are looking for is

str = str.split("[\\(\\)]")[1];

This would split by parenthesis. It translates into split by ( or ). you use the double \\ to escape the paranthese which is a reserved character for regular expressions.

If you wanted to split by a . you would have to use split("\\.") to escape the dot as well.

Answer 3

You could try:

String str = "United Arab Emirates Dirham (AED)";
int firstBracket = str.indexOf('(');
String contentOfBrackets = str.substring(firstBracket + 1, str.indexOf(')', firstBracket));

Answer 4

Compiles and prints "AED". Even works for multiple parenthesis:

import java.util.regex.*;

public class Main
{
  public static void main (String[] args)
  {
     String example = "United Arab Emirates Dirham (AED)";
     Matcher m = Pattern.compile("\\(([^)]+)\\)").matcher(example);
     while(m.find()) {
       System.out.println(m.group(1));    
     }
  }
}

The regex means:

• \\(: character (
• (: start match group
• [: one of these characters
• ^: not the following character
• ): with the previous ^, this means "every character except )"
• +: one of more of the stuff from the [] set
• ): stop match group
• \\): literal closing paranthesis

Answer 5

yes, you can try different techniques like using

 string.indexOf("("); 

to get the index and the use

string.substring(from, to)

Answer 6

The answer from @Cœur is probably correct, but unfortunately it did not work for me. I had text similar to this:

mrewrwegsg {text in between braces} njanfjaenfjie a {text in between braces}

It was way larger, but let's consider only this short part.

I used this code to get each text between bracelet and print it to the console:

Pattern p = Pattern.compile("\\{.*?\\}");
Matcher m = p.matcher(test);
while(m.find()) {
      System.out.println(m.group().subSequence(1, m.group().length()-1));
}

It might be more complicated than @Cœur answer, but maybe there is someone like me, who can find my answer useful.