how to read file from line x to the end of a file in bash

Question

I would like know how I can read each line of a csv file from the second line to the end of file in a bash script.

I know how to read a file in bash:

Answer 1

Or else (pure bash)...

{ for ((i=1;i--;));do read;done;while read line;do echo $line;done } < file.csv

Better written:

linesToSkip=1
{
    for ((i=$linesToSkip;i--;)) ;do
        read
        done
    while read line ;do
        echo $line
        done
} < file.csv

This work even if linesToSkip == 0 or linesToSkip > file.csv's number of lines

Edit:

Changed () for {} as gniourf_gniourf enjoin me to consider: First syntax generate a sub-shell, whille {} don't.

of course, for skipping only one line (as original question's title), the loop for (i=1;i--;));do read;done could be simply replaced by read:

{ read;while read line;do echo $line;done } < file.csv