Remove substring only at the end of string

Question

I have a bunch of strings, some of them have \' rec\'. I want to remove that only if those are the last 4 characters.

So in other words I have

Answer 1

You could use a regular expression as well:

from re import sub

str = r"this is some string rec"
regex = r"(.*)\srec$"
print sub(regex, r"\1", str)

Answer 2

Here is a one-liner version of Jack Kelly's answer along with its sibling:

def rchop(s, sub):
    return s[:-len(sub)] if s.endswith(sub) else s

def lchop(s, sub):
    return s[len(sub):] if s.startswith(sub) else s

Answer 3

def remove_trailing_string(content, trailing):
    """
    Strip trailing component `trailing` from `content` if it exists.
    """
    if content.endswith(trailing) and content != trailing:
        return content[:-len(trailing)]
    return content

Answer 4

use:

somestring.rsplit(' rec')[0]

Answer 5

Using more_itertools, we can rstrip strings that pass a predicate.

Installation

> pip install more_itertools

Code

import more_itertools as mit


iterable = "this is some string rec".split()
" ".join(mit.rstrip(iterable, pred=lambda x: x in {"rec", " "}))
# 'this is some string'

" ".join(mit.rstrip(iterable, pred=lambda x: x in {"rec", " "}))
# 'this is some string'

Here we pass all trailing items we wish to strip from the end.

See also the more_itertools docs for details.

Answer 6

As kind of one liner generator joined:

test = """somestring='this is some string rec'
this is some string in the end word rec
This has not the word."""
match = 'rec'
print('\n'.join((line[:-len(match)] if line.endswith(match) else line)
      for line in test.splitlines()))
""" Output:
somestring='this is some string rec'
this is some string in the end word 
This has not the word.
"""