Radius of “viewable” region in google maps v3

前端 未结 4 1693
渐次进展
渐次进展 2020-12-22 22:41

I need to know how to retrieve the radius of the viewable zoom level in google maps API v3.

For example, if I am at zoom level 3, and depending on the users screen s

相关标签:
4条回答
  • 2020-12-22 23:07

    I believe Bounds have the getNorthEast() and getSouthWest() methods, but this would give you a rectangle (which bounds really is) and you could than calculate the distance between those two, etc. To calculate the circle out of that rectandle might be a bit of work...

    Maybe this will help: http://code.google.com/apis/maps/articles/mvcfun.html

    and the example: http://code.google.com/apis/maps/articles/mvcfun/step6.html

    0 讨论(0)
  • The radius would equal the distance from the center of the bounds to one of the bound's corners. Using the Great Circle Distance Formula from the calculations from this page, I came up with the following:

    var bounds = map.getBounds();
    
    var center = bounds.getCenter();
    var ne = bounds.getNorthEast();
    
    // r = radius of the earth in statute miles
    var r = 3963.0;  
    
    // Convert lat or lng from decimal degrees into radians (divide by 57.2958)
    var lat1 = center.lat() / 57.2958; 
    var lon1 = center.lng() / 57.2958;
    var lat2 = ne.lat() / 57.2958;
    var lon2 = ne.lng() / 57.2958;
    
    // distance = circle radius from center to Northeast corner of bounds
    var dis = r * Math.acos(Math.sin(lat1) * Math.sin(lat2) + 
      Math.cos(lat1) * Math.cos(lat2) * Math.cos(lon2 - lon1));
    

    After playing some more with this, I've noticed that map.getBounds() will contain the full map viewport. But if your LatLngBounds is built by extending to include LatLng points, and then you issue a map.fitBounds(bounds), the api increases the map's viewport a bit so that the bounds "box" has some padding.

    If you use the map's current viewport, the radius from the center to the corner of the viewport might be a longer radius than you want. Maybe the distance from the viewport center to the middle of the furthest viewport edge. (If the map isn't a perfect square)

    0 讨论(0)
  • 2020-12-22 23:09

    I also refactored Eric's answer, mine is as a standalone function, and am returning the result in meters (as needed by the Places API search.

    function getBoundsRadius(bounds){
      // r = radius of the earth in km
      var r = 6378.8
      // degrees to radians (divide by 57.2958)
      var ne_lat = bounds.getNorthEast().lat() / 57.2958
      var ne_lng = bounds.getNorthEast().lng() / 57.2958
      var c_lat = bounds.getCenter().lat() / 57.2958
      var c_lng = bounds.getCenter().lng() / 57.2958
      // distance = circle radius from center to Northeast corner of bounds
      var r_km = r * Math.acos(
        Math.sin(c_lat) * Math.sin(ne_lat) + 
        Math.cos(c_lat) * Math.cos(ne_lat) * Math.cos(ne_lng - c_lng)
        )
      return r_km *1000 // radius in meters
    }
    
    0 讨论(0)
  • 2020-12-22 23:13

    Refactored version of Eric's answer above using google.maps.geometry.spherical namespace (make sure you loaded Geometry library to make this work).

    var bounds = map.getBounds();
    var center = map.getCenter();
    if (bounds && center) {
      var ne = bounds.getNorthEast();
      // Calculate radius (in meters).
      var radius = google.maps.geometry.spherical.computeDistanceBetween(center, ne);
    }
    
    0 讨论(0)
提交回复
热议问题