How to find that a word/words in a column is present in another column consisting a sentence [duplicate]

Answer 1

Or use a dplyr & stringr solution. But in principle its the same idea:

library(tidyverse)
library(stringr)
df %>% 
  mutate(result=str_detect(df$string,gsub(" ", "|", df$substring)))
                 substring                 string result
1             my new phone this is a mobile phone   TRUE
2 She would buy new phones Yes, I have two phones   TRUE
3            telephonessss       my old telephone  FALSE
4             telephone234           telephone234   TRUE

Answer 2

This should work for you:

df[, "lookup"] <- gsub(" ", "|", df[,"substring"])
df[,"t"] <- mapply(grepl, df[,"lookup"], df[,"string"])

df
#                 substring                 string                   lookup     t
#1             my new phone this is a mobile phone             my|new|phone  TRUE
#2 She would buy new phones Yes, I have two phones She|would|buy|new|phones  TRUE
#3            telephonessss       my old telephone            telephonessss FALSE
#4             telephone234           telephone234             telephone234  TRUE

You could get more fancy with creating the lookup column, but for this case there is no need so I used a simple gsub.

---

Data:

df <- data.frame(substring = c("my new phone", "She would buy new phones", "telephonessss", "telephone234"),
                 string = c("this is a mobile phone", "Yes, I have two phones", "my old telephone", "telephone234"))