Create a copy of the list not referencing the contained objects

Question

Say I have a vector a defined as:

a = [[1,2,3],[-1,-2,-3]]

I have learned that to create a copy of the object a w

Answer 1

If you only "shallow copy" b = a[:], each sub-list b[n] is still a reference to the same sub-list referenced at a[n]. Instead you need to do a deep(er) copy, e.g. by

b = [l[:] for l in a]

This creates a shallow copy of each sub-list, but as their contents are immutable that isn't a problem. If you have more levels of container nesting, you need copy.deepcopy as the other answers suggest.

Answer 2

a[:] creates a shallow copy of the list.

You can use the copy.deepcopy() function to recursively copy the objects, or use a list comprehension:

b = [el[:] for el in a]

This creates a new list object with shallow copies of the nested list objects in a.

Answer 3

Use copy.deepcopy

import copy
b = copy.deepcopy(a)

Quoting the docs:

A deep copy constructs a new compound object and then, recursively, inserts copies into it of the objects found in the original

Example:

>>> a = list(range(1000))
>>> b = copy.deepcopy(a)
>>> a is b    # b is a new object
False
>>> 

Answer 4

For that use deepcopy:

>>> from copy import deepcopy
>>> b = deepcopy(a)

>>> b[0][2] = 'change a'
>>> print a
[[1,2,3],[-1,-2,-3]]

Deepcopy: https://docs.python.org/2/library/copy.html#copy.deepcopy

Extension

Deepcopy also creates an individual copy of class instances. Please see simple example below.

from copy import deepcopy

class A:
    def __init__(self):
        self.val = 'A'

>>> a = A()
>>> b = deepcopy(a)

>>> b.val = 'B'
>>> print a.val
'A'
>>> print b.val
'B'