Exception in thread main java.util.InputMismatchException error

Question

I have a question on what\'s going on, whenever I try to compile it it keeps giving me an error like this:

Exception in thread \"main\" java.util.InputMismat         


        

Answer 1

It means that your program has tried to read a value that as an integer that is not an integer.

when using name = in.nextInt();

it should be string.not int

Answer 2

import java.util.*;
class Employe
{
    private int id;
    private String name;
    Employe(int id,String name)
    {
        this.id=id;
        this.name=name;
    }
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
}
public class Quarantine {
public static void main(String[] args) {
    Employe empList[]=new Employe[2];
    Scanner sc=new Scanner(System.in);
    for(int index=0;index<empList.length;index++) {
    int id=sc.nextInt();
    String name=sc.nextLine(); 
    empList[index]=new Employe(id,name);
    }
    for(int index=0;index<empList.length;index++) {
        System.out.println(empList[index].getId()+" "+empList[index].getName());
        }}
}

if I give input as 1, a

it will show error because both are taken as character

I need to give input as 124, a run

Answer 3

Issues

 int name; //Name should be of type String
 ...
 System.out.println("Enter in your name");
 name = in.nextInt(); //It doesn't handle the string since your using `nextInt`

Solution

 String name;
 ...
 System.out.println("Enter in your name");
 name = in.nextLine();

Answer 4

name = in.nextInt(); as you required user name so obviously it will be String type so use either name=in.next() or name=in.nextLine(). i hope it will work now.

Answer 5

Why is name an integer? int name;

I suspect you are using alpha characters to input your name...and are getting the exception at this line: name = in.nextInt();

name should not be an integer. It should be a string.

Therefore, string name; and name = in.nextLine();