Mixedorder data frame in R [duplicate]

Answer 1

I'd just split the column. If you want numeric order for the numbers part of the ID, you should probably have these numbers as a numeric column anyway.

ab$a1 <- as.numeric(gsub("[[:alpha:]+]", "", ab$a))
ab$a2 <- gsub("\\d+", "", ab$a)

ab[order(ab$a1, ab$a2),]
#    a b a1 a2
#1  1A 1  1  A
#4  2B 4  2  B
#5  2C 5  2  C
#7  3A 7  3  A
#8  3B 8  3  B
#2 10A 2 10  A
#3 11A 3 11  A
#6 22C 6 22  C

Answer 2

We need to convert to character class (as the 'a' column is factor based on the default option in data.frame call i.e. stringsAsFactors=TRUE)

ab[mixedorder(as.character(ab$a)),]
#    a b
#1  1A 1
#4  2B 4
#5  2C 5
#7  3A 7
#8  3B 8
#2 10A 2
#3 11A 3
#6 22C 6

Additional options are also explained in here