Comparing two editTexts in android

Question

I am learning android I tried following codeline but it\'s giving me error please give me suggestions, that how can I compare two edittext\'s text.

Answer 1

if( (edt1.getText().toString()=="X")&&(edt4.getText().toString()=="X")&&(edt7.getText().toString()=="X") )

Answer 2

if you want to check edt1, edt4, edt7 have "X" value then try this..

if((edt1.getText().toString().equalsIgnoreCase("X")     
               &&edt4.getText().toString().equalsIgnoreCase("X") && 
              edt7.getText().toString.equalsIgnoreCase("X"))

Answer 3

Make it simple:

if (!et1.toString().equals(et2.toString())) {
    MsgBox(this,"--Your Message--");
}

Answer 4

Please try this:

if((edt1.getText().toString.equalsIgnoreCase("X")) && 
   (edt4.getText().toString.equalsIgnoreCase("X")) && 
   (edt7.getText().toString.equalsIgnoreCase("X")))

If you have to compare strings then you need to call the equals or equalsIgnoreCase function of String.

Answer 5

Here's a solution that doesn't violate the DRY principle:

private static boolean allContain(final String value, 
                                  final EditText... editTexts)
{

    for (EditText editText : editTexts) {
        final String text = editText.getText().toString();
        if (!text.equals(value)) {
            return false;
        }
    }
    return true;
}

You can use it as follows:

if (allContain("X", edt1, edt2, edt3, edt4)) {
    // All EditTexts contain 'X'
}

Answer 6

I have find the best solution..

if(Password.getText().toString().trim().matches(confirmPassword.getText().toString().trim()))
{
// then do your work
}
else
//otherwise show error message.

whereas

Password = (EditText)findViewById(R.id.pass);

confirmPassword = (EditText)findViewById(R.id.confirmpass);

are two editText.