mysql_result() expects parameter 1 to be resource, boolean given [duplicate]

Answer 1

Your query is wrong. Try replacing with below one

$query = "SELECT COUNT(*) FROM  users  WHERE  active = 1";

You should have some mysql error handling implemented to avoid such type of warnings.

Suggestion: Better to use PDO to talk your database

Answer 2

In mysql count is a function so you should use COUNT(*) and not COUNT *

You should also consider tracking errors with functions like mysql_error when the mysql_query function returns false and not a resource

also, the common side note: think about switching to PDO

Answer 3

function user_count(){
    $query = "SELECT COUNT(user_id) FROM  `users` WHERE  `active` = 1";
    $result = mysql_query($query) or die($query."<br/><br/>".mysql_error());
    return mysql_result($result, 0);
}

This works.