asp.net mvc validation annotation for dollar currency

Question

I am validation for Html.TextBoxFor. Here is my code on the view

@Html.TextBoxFor(m => m.Amount, new {@class = \"form-control\", Value = Stri         


        

Answer 1

When you do the value = string.Format("{0:C}", Model.Amount) in the htmlAttributes, razor will execute the C# code and return the value,"$125.67", (Assuming the value of your Amount property is 125.67M) which is a string. So the markup generated by your view will be

<input value="$125.67" class="form-control" id="Amount" name="Amount" type="text">

Now since $125.67 is not not a valide decimal value, but a string. it cannot map the value of this textbox to the Amount property of your view model which is of type decimal/doube.

What you can do is, create a new property in your view model of type string to store this formatted string value and when user submits the form, try to parse it back to a decimal variable and use it.

So add a new property to your view model

public class CreateOrderVm
{
  public int Id { set;get;}
  public string AmountFormatted { set;get;}  // New property
  public decimal Amount  { set;get;}
}

And in your view, which is strongly typed to CreateOrderVm

@model CreateOrderVm
@using(Html.BeginForm())
{
    @Html.TextBoxFor(m => m.AmountFormatted, new { @class = "form-control",
                                Value = String.Format("{0:C}", Model.Amount) })

    <input type="submit" />
}

And in your HttpPost action

[HttpPost]
public ActionResult Create(CreateOrderVm model)
{
    decimal amountVal;

    if (Decimal.TryParse(vm.AmountFormatted, NumberStyles.Currency,
                                             CultureInfo.CurrentCulture, out amountVal))
    {
        vm.Amount = amountVal;
    }
    else
    {
       //add a Model state error and return the model to view,
    }

    //vm.Amount has the correct decimal value now. Use it to save
    // to do  :Return something
}

Answer 2

You can create you own Binder object to handle this. First create this object:

public class DoubleModelBinder : IModelBinder
{
  public object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
  {
    ValueProviderResult valueResult = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);
    ModelState modelState = new ModelState { Value = valueResult };
    object actualValue = null;
    try
    {
      if (!string.IsNullOrEmpty(valueResult.AttemptedValue))
        actualValue = Convert.ToDouble(valueResult.AttemptedValue.Replace("$", ""), System.Globalization.CultureInfo.CurrentCulture);
    }
    catch (FormatException e)
    {
      modelState.Errors.Add(e);
    }

    if (bindingContext.ModelState.ContainsKey(bindingContext.ModelName))
      bindingContext.ModelState[bindingContext.ModelName] = modelState;
    else
      bindingContext.ModelState.Add(bindingContext.ModelName, modelState);
    return actualValue;
  }
}

Then in your Global.asax.cs file in the Application_Start function, add this:

ModelBinders.Binders.Add(typeof(double?), new DoubleModelBinder());