Combine file modified date and “grep” results through “find”, in one line

Question

We want to show each file\'s modified date and time when applying grep to selected files by the find command. The final result should look like:

Answer 1

You can use this find+grep combination to get the formatted result:

while IFS=$'\06' read -r -d '' t f; do
   sed "s/^/$t /" <(grep -HTni 'σχόλια' "$f")
done < <(find . -type f -mmin -10 -not \( -path ./admin -prune \) \
         -not \( -path ./people/languages -prune \) \
         -not \( -path ./include -prune \) \
         -printf '%TY-%Tm-%Td %Ta %TH:%TM:%.2TS\06%p\0')

• Note use of \06 as field delimiter to address filenames/paths with whitespaces/newlines etc.
• \0 (NULL) is used as line terminator for the same reason.
• %.2TS is used to trip fractional part of the second value.
• sed is used to insert date/time at line start of grep output.

---

PHP Code:

$cmd = <<<'EOF'
export TZ=":Europe/Athens"; \
find . -type f -mmin -10 -not \( -path ./admin -prune \) \
       -not \( -path ./people/languages -prune \) \
       -not \( -path ./include -prune \) \
       -printf '%TY-%Tm-%Td %Ta %TH:%TM:%.2TS\06%p\0' |
while IFS=$'\06' read -r -d '' t f; do grep -HTni 'σχόλια' "$f" | sed "s/^/$t /"; done
EOF;

// var_dump( $cmd );

echo shell_exec($cmd) . "\n";