How do I loop through a PHP array containing data returned from MySQL?

Question

Ok I have a table with a few fields. One of the fields is username. There are many times where the username is the same, for example:

Answer 1

I like to separate the DB logic from the display. I generally put my results into an array that I can call within the HTML code. Purely personal preference; but here's how'd I'd approach the problem: (I'd take the $sql out of the error message in production)

<?php
$sql="
  SELECT *
  FROM auth
  WHERE username='$user';
  ";
$result = mysql_query($sql)
  or die("Failed Query : ".mysql_error() . $sql);  //do the query

while ($ROW = mysql_fetch_array($result,MYSQL_ASSOC)) {
  $USERS[] = $ROW;
}
?>

HTML CODE

<? foreach ($USERS as $USER) { ?>

Study: <?=$USER['dbFieldName'];?> - <?=$USER['dbFieldName2'];?>

<? } //foreach $USER ?>

Answer 2

I suggest you to read this: http://www.w3schools.com/php/php_mysql_select.asp It will give you an overview idea of how to properly connect to mysql, gather data etc

For your question, you should use a loop:

while ($row = mysql_fetch_row($result)){//code}

As said by htw

Answer 3

You can also obtain a count of all rows in a table like this:

    $count = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS count FROM table"));
    $count = $count["count"];

You can also append a normal WHERE clause to the select above and only count rows which match a certain condition (if needed). Then you can use your count for loops:

    $data = mysql_query("SELECT * WHERE username='bob'");
    for ($i = 0; $i 

Also, mysql_fetch_array() is usually a lot easier to use as it stores data in an associative array, so you can access data with the name of the row, rather than it's numeric index.

Edit: There's some kind of bug or something going on where my second code block isn't showing everything once it's posted. It shows fine on the preview.

Answer 4

$qry=mysql_query(select * where username='bob');

if(mysql_num_rows($qry))

{

 while($row=mysql_fetch_array($qry,MSQL_NUM))

 {

        echo $row[0]."&nbsp;&nbsp;".$row[1]."&nbsp;&nbsp;".$row[2]."<br>";

 }

}

Answer 5

Use a loop, and use mysql_fetch_array() instead of row:

while($row = mysql_fetch_array($result)) {
   echo "Study: " . $row[1] . " - " . $row[5];
   // but now with mysql_fetch_array() you can do this instead of the above
   // line (substitute userID and username with actual database column names)...
   echo "Study: " . $row["userID"] . " - " . $row["username"];
}

Answer 6

mysql_fetch_row fetches each row one at a time. In order to retrieve multiple rows, you would use a while loop like this:

while ($row = mysql_fetch_row($result))
{
    // code
}