mysqli bind_param() fatal error

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傲寒
傲寒 2020-12-21 15:36

I Have an Error at my Code could someone help me?



        
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  • 2020-12-21 16:04

    it should be $stmt->bind_result($name, $kalender_ID);

    drop the s

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  • 2020-12-21 16:07

    One of your fields on this line doesn't exist,check them.

    $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?";
    

    Also, you should be checking for $stmt.

    $db = new mysqli("localhost","root","","karmintalender");
    
     $owner_ID = 1;
    
     $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?";
     $stmt = $db->prepare($sql);
     if($stmt){
         $stmt->bind_param("i", $owner_ID);
         $stmt->execute();
         $stmt->bind_results($name, $kalender_ID);
    
         while ($stmt->fetch()) {
           echo $name . " " . $kalender_ID;
         }
     }
    
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