Trailing Sum Query

Question

I am looking to summarize date and need to find a way of doing a 3 day trailing sum, sum of the current date and the 2 previous days. I am using MariaDB, a MYSQL fork.

Answer 1

A fast way using MySQL variables

Sample table:

create table keywordsum (date datetime, total int);
insert keywordsum values
('2010-11-11',316815),
('2010-11-12',735305),
('2010-11-13',705116),
('2010-11-14',725020),
('2010-11-15',745378);

Query:

select
  k.date, k.total, k.total + ifnull(@d1,0) + ifnull(@d2,0) running_total,
  @d2 := @d1,
  @d1 := k.total
from (select @d1 := null, @d2 := null) vars
cross join keywordsum k
order by k.date

(You can always subselect this to get only the first 3 columns)

Answer 2

One simple way is to join the table to itself. Make sure it is indexed on a combination of date and total.

select t1.date
     , t1.total
     , t1.total 
      +coalesce(t2.total,0)
      +coalesce(t3.total,0)
  from theTable t1
  left 
  join theTable t2 on t1.date = date_Add(t2.date,interval 1 day)
  left
  join theTable t3 on t1.date = date_Add(t3.date,interval 2 day)