Sorting of XML file by XMLElement's InnerText

Question

Please have a look at the XML file. I would like to sort the XML file by tag

  
    ABC&         


        

Answer 1

Have you tried,

XElement root = XElement.Load(xmlfile);
var orderedtabs = root.Elements("Tab")
                      .OrderBy(xtab => (int)xtab.Element("Order"))
                      .ToArray();
root.RemoveAll();
foreach(XElement tab in orderedtabs)
    root.Add(tab);
root.Save(xmlfile);

Answer 2

Basically, you need to parse the XML file into a set of records, sort the records on the appropriate field, then write the result back out as a new XML file.

Answer 3

if you use using System.Xml.Linq;

then you can get the sorted xlements like this

var xnodes = oldXDoc.Element("MyRootNode").Elements();
var sortedXNodes = xnodes.OrderBy(node => Convert.ToInt32( node.Element("Order").Value));
var newXdoc = new XDocument(new XElement("MyRootNode", sortedXNodes));

Answer 4

use XSLT

E.g:

dataSort.xslt:

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
    <xsl:element name="MyRootNode">
        <xsl:apply-templates select="MyRootNode" />
    </xsl:element>
</xsl:template>

<xsl:template match="MyRootNode">
    <xsl:for-each select="Tab">
        <xsl:sort select="Order/text()" data-type="number"/>
            <xsl:copy-of select="." />
    </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Sample.cs:

//convert data.xml to sortedData.xml

using System;
using System.Xml.Xsl;

class Sample {
    static public void Main(){
        XslCompiledTransform xslt = new XslCompiledTransform();
        xslt.Load("dataSort.xslt");
        xslt.Transform("data.xml", "sortedData.xml");
    }
}