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Unable to parse xml data with colon (:) from response using getNamespaces()

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面向向阳花
面向向阳花 2020-12-21 09:43

I want to read whatever is inside the tags in the following xml -

$xml = \'
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  • 醉酒成梦
    2020-12-21 10:47

    I have no problem to get it to work, the only error I could find is that you're loading XML containing a non-XML HTML chunk in there which is breaking the document: The meta elements in the head section are not closed.

    See Demo.

    Tip: Always activate error logging and reporting, check for warnings and notices if you develop and debug code. A short one-line displaying all sort of PHP error messages incl. warnings, notices and strict:

    error_reporting(-1); ini_set('display_errors', 1);

    DOMDocument is talkative then about malformed elements when loading XML.

    Fixing the XML "on the fly"

    DomDocument accepts only valid XML. If you've got HTML you can alternatively try if DOMDocument::loadHTML() does the job as well, however it will convert the loaded string into a X(HT)ML document then. Probably not what you're looking for.

    To escape a specific part of the string to load to make it XML compatible you can search for string patterns to obtain the substring that represents the HTML inside the XML and properly XML encode it.

    E.g. you can look for <html> and </html> as the surrounding tags, extract the substring of the whole and replace it with substr_replace(). To encode the HTML for being used as data inside the XML, use the htmlspecialchars() function, it will replace everything with the five entities in the other SO answer.

    Some mock-up code:

    $htmlStart = strpos($xml, '<html>');
if (false === $htmlStart) throw new Exception('<html> not found.');
$htmlEnd = strpos($xml, '</html>', $htmlStart);
if (false === $htmlStart) throw new Exception('</html> not found.');
$htmlLen = $htmlEnd - $htmlStart + 7;
$htmlString = substr($xml, $htmlStart, $htmlLen);
$htmlEscaped = htmlspecialchars($htmlString, ENT_QUOTES);
$xml = substr_replace($xml, $htmlEscaped, $htmlStart, $htmlLen);
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