Log Parsing with Regex

Question

I\'m trying to parse an Apache Log with regex using Python and assign it to separate variables.

ACCESS_LOG_PATTERN = \'^(\\S+) (\\S+) (\\S+) \\[([\\w:/]+\\s[         


        

Answer 1

You need to make your group 7 optional by adding a ?. Use the following regex:

^(\S+) (\S+) (\S+) \[([\w:/]+\s[+\-]\d{4})\] "(\S+) (\S+)\s*(\S+)?\s*" (\d{3}) (\S+)
                                                                 ↑

See the DEMO

Answer 2

import re


HOST = r'^(?P<host>.*?)'
SPACE = r'\s'
IDENTITY = r'\S+'
USER = r'\S+'
TIME = r'(?P<time>\[.*?\])'
REQUEST = r'\"(?P<request>.*?)\"'
STATUS = r'(?P<status>\d{3})'
SIZE = r'(?P<size>\S+)'

REGEX = HOST+SPACE+IDENTITY+SPACE+USER+SPACE+TIME+SPACE+REQUEST+SPACE+STATUS+SPACE+SIZE+SPACE

def parser(log_line):
    match = re.search(REGEX,log_line)
    return ( (match.group('host'),
            match.group('time'), 
                      match.group('request') , 
                      match.group('status') ,
                      match.group('size')
                     )
                   )


logLine = """180.76.15.30 - - [24/Mar/2017:19:37:57 +0000] "GET /shop/page/32/?count=15&orderby=title&add_to_wishlist=4846 HTTP/1.1" 404 10202 "-" "Mozilla/5.0 (compatible; Baiduspider/2.0; +http://www.baidu.com/search/spider.html)"""
result = parser(logLine)
print(result)

RESULT

('180.76.15.30', '[24/Mar/2017:19:37:57 +0000]', 'GET /shop/page/32/?count=15&orderby=title&add_to_wishlist=4846 HTTP/1.1', '404', '10202')