Euclidean distance of points coordinates in pandas dataframe

Question

I have a pandas dataframe with six columns, first three columns contain x, y and z reference coordinate, and the next three - coordinates of some

Answer 1

Here's how I do it:

p1 = df[['x1', 'y1', 'z1']]
p2 = df[['x2', 'y2', 'z2']]

df['dist'] = ((p1 - p2)**2).sum(axis=1) ** 0.5

Answer 2

You might not need any fancy magic here:

df['dist'] = np.sqrt( (df.x1-df.x2)**2 + (df.y1-df.y2)**2 + (df.z1-df.z2)**2)