Exclude rows based on other rows (SQL)

Question

Say I have a query like this:

SELECT *
FROM TABLE

And it returns this:

TABLE
ID | DATA | VAL
===============
01 | ABCD | 1
         


        

Answer 1

you could use a minus operator.

pseudo-query

select everything
from tables
where id in ( select id from table minus select id from table where val is bad )

Answer 2

you could try something like

SELECT *
FROM TABLE
WHERE TABLE.ID NOT IN(
    SELECT ID
    FROM TABLE
    WHERE TABLE.VAL < '1'
    OR TABLE.VAL > '3'
)

Answer 3

Here is another alternative that will pass through TBL once, aggregate, and using the IDs found, retrieve the data from TBL

SELECT *
WHERE ID IN
(
    SELECT
       ID,
       CASE WHEN val in (1,2,3) THEN 1 ELSE 0 END Test
    FROM TBL
    GROUP BY ID
    HAVING MIN(val) = 1
)

For multi-column keys, and as an alternative to the above IN form, you can use the JOIN form.

SELECT T.*
FROM (
    SELECT
       Company, OrderNumber,
       CASE WHEN val in (1,2,3) THEN 1 ELSE 0 END Test
    FROM TBL
    GROUP BY Company, OrderNumber
    HAVING MIN(val) = 1
    ) KEEP
INNER JOIN TBL T ON T.Company = KEEP.Company and T.OrderNumber=KEEP.OrderNumber

Answer 4

Use:

SELECT * 
  FROM TABLE a
 WHERE a.val IN (1,2,3)
   AND NOT EXISTS(SELECT NULL
                    FROM TABLE b
                   WHERE b.id = a.id
                     AND b.val NOT IN (1, 2, 3))