c++ publicly inherited class member cannot be used as default argument

Question

A schematic of my problem...

class A
{
public:
    // etc.
protected:
    uint num;
};

class B : public A
{
public: 
    void foo(uint x = num); //bad
};


        

Answer 1

you can create 2 foos

foo() //use num internally

foo(int x) //use x

Answer 2

You can use overloading instead of default arguments.

class A
{
public:
    // etc.
protected:
    uint num;
};

class B : public A
{
public: 
    void foo(uint x);
    void foo() { foo( num ); }
};

Answer 3

I suspect this happens (based on the complaint about non-staticness) because there is no this pointer for it to use to know which instance of B it should get num from.

The Microsoft compiler (at least) allows you to specify an expression, but not a non-static member. From MSDN:

The expressions used for default arguments are often constant expressions, but this is not a requirement. The expression can combine functions that are visible in the current scope, constant expressions, and global variables. The expression cannot contain local variables or non-static class-member variables.

Work-arounds for this are numerous and others have pointed out a few. Here's one more which you may or may not like:

void foo(uint* x = NULL) {
  uint y = (x == NULL ? num : *x);
  // use y...
}