The Ternary Operator in PHP [duplicate]

Answer 1

This is because the ternary operator (?:) is left associative so this is how it's getting evaluated:

((1 == 1) ? "one" : (1 == 2)) ? "two" : "three"

So 1 == 1 -> TRUE means that then it's:

"one" ? "two" : "three"

And "one" -> TRUE so the output will be:

two

Answer 2

$chow = 1;
echo ($chow == 1) ? "one" : (($chow == 2) ? "two" : "three");

remember to use brackets when result of operation can be unclear

now output is one

Answer 3

The operator is confused, you need to put brackets around your second codition. use the code below

$chow = 1;
echo ($chow == 1) ? "one" : (($chow == 2) ? "two" : "three"); //returns 1

Hope this helps you