Regex match string that ends with number

Question

What is a regex to match a string that ends with a number for example

\"c1234\" - match
\"c12\" - match
\"c\" - no match

Tried this but it

Answer 1

dynamic way would be:

import re
word_list = ["c1234", "c12" ,"c"]
for word in word_list:
    m = re.search(r'.*\d+',word)
    if m is not None:
        print(m.group(),"-match")
    else:
        print(word[-1], "- nomatch")

RESULT:

c1234 -match
c12 -match
c - nomatch

Answer 2

You can use this regular expression pattern

^c[0-9]+$

Answer 3

"(c|C).*[0-9]$"

See working example: https://regex101.com/r/4Q2chL/3

Answer 4

To match any string ending with a digit use: [\s\S]*\d$

if (preg_match('/[\s\S]*\d$/', $value)) {
   #match
} else {
  #no match
}

Answer 5

Just use

\d$

to check your string ends with a digit

If you want your string to be a "c" followed by some digits, use

c\d+$