How can I create a new thread AddressOf a function with parameters in VB?

Question

When option strict is OFF, works fine. ON, I get overload resolution failure:

Dim _thread1 As Thread

Private Sub test2(boolTest As Boolean)
    \' Do someth         


        

Answer 1

You should follow al-eax's answer, but another way would be to not pass parameters in the Thread.Start() function at all, but rather evaluate it in the test sub...

Dim _thread1 As Thread

Private Sub test()
    If someTest = True then    
        _thread1 = New Thread(AddressOf test2)
        _thread1.Start()
    End If
End Sub

Private Sub test2()
    /.../
End Sub

...or declare it as a global variable...

Dim _thread1 As Thread
Dim boolTest As Boolean

Private Sub test()
    boolTest = True

    _thread1 = New Thread(AddressOf test2)
    _thread1.Start()
End Sub

Private Sub test2()
    If boolTest = True Then
        /.../
    End If
End Sub

Answer 2

When you start a thread this way your function must have one or less parameters. If you specify one parameter, it must be from type Object.

In your function you can simply cast this object parameter to your datatype:

private sub startMe(byval param as Object)
     dim b as Boolean = CType(param, Boolean)
     ...
end sub

When you want to pass multiple parameters, you can put them together into a class like this:

public class Parameters
     dim paramSTR as String
     dim paramINT as Integer
end class

private sub startMe(byval param as Object)
     dim p as Parameters = CType(param, Parameters)
     p.paramSTR = "foo"
     p.paramINT = 0
     ...
end sub

To start your Thread:

dim t as new Thread(AddressOf startMe)
dim p as new Parameters
p.paramSTR = "bar"
p.oaramINT = 1337
t.start(p)

Answer 3

It looks like it's because the method you're delegating to has a Boolean parameter: '...does not allow narrowing...' Change the signature to use Object.