Sort strings by using “less/greater than” comparison operators in comparator

Question

Today I found a strange for me implementation of strings sorting:

[\'Data\', \'Chata\', \'Clata\'].sort(function(a, b) { return a > b});

Answer 1

I'm not entirely sure how it manages to work.

EDIT it actually doesn't.

I produced a test using 1000 numbers (https://jsfiddle.net/alnitak/80cje6gt/) and the single comparator doesn't produce the correct sort order:

var m = 0;
a.sort(function(a, b) { ++m; return a > b} );

var n = 0;
b.sort(function(a, b) { ++n; return a < b ? -1 : a > b ? 1 : 0});

Answer 2

When comparing strings, comparison is done letter by letter. So c has lower symbol value than d (Check this table)