MySQL: select 5 rows before and after specific row

Question

I have table called \"users\" and need to select 2 rows before and after specific row, sorted by users.score ASC

users table (structure):

id     name         


        

Answer 1

(SELECT x.* FROM users x JOIN users y ON y.score <= x. score WHERE y.id = 5 ORDER BY score LIMIT 3)
UNION
(SELECT x.* FROM users x JOIN users y ON y.score >= x. score WHERE y.id = 5 ORDER BY score DESc LIMIT 3)
[ORDER BY score]    ;

http://www.sqlfiddle.com/#!9/45c22/42

Answer 2

Selecting arbitrarily ordered rows before and after a specific id

SET @j = 0;
SET @i = 0;
SELECT *
FROM ( 
    SELECT id, col1, col2, ..., @j:=@j+1 AS pos
    FROM `table`
    WHERE  col1=... ORDER BY col1 DESC, col2 ASC
) AS zz
WHERE (    
    SELECT position
    FROM ( 
        SELECT id AS id2, @i:=@i+1 AS position
        FROM `table`
        WHERE  col1=... ORDER BY col1 DESC, col2 ASC
    ) AS zz
    WHERE id2=$currId
)
IN (pos-5,pos-4,pos-3,pos-2,pos-1,pos,pos+1,pos+2,pos+3,pos+4,pos+5)

Answer 3

Using union all and subqueries to limit the records should do it:

select * from  users where id = 5
union all (
  select * from users 
  where score <  (select score from users where id = 5) 
  order by score desc limit 2
) 
union all (
  select * from users 
  where score > (select score from users where id = 5) 
  order by score asc limit 2
) 
order by score

Sample SQL Fiddle

Edit: I think a better method is to number the rows according to score and then select the rows with number -2 and +2 from the rows of id 5:

select id, name, score 
from (select 
      t.*, @rownum1 := @rownum1 + 1 as rank
      from users t, (select @rownum1 := 0) r
      order by score
     ) a,
     (select rank from (
        select t.*, 
        @rownum := @rownum + 1 as rank
        from users t, (select @rownum := 0) r
        order by score
     ) t
      where id = 5
   ) b
where b.rank between a.rank -2 and a.rank+2
order by score;    

Sample SQL Fiddle

Answer 4

I just write the query, based on "jpw" solution (many thanks to him)

select * from  users where id = 5
union all (
  select * from users 
  where id in (select id from users where score < (select score from users u where u.id = 5) order by score ASC)
  order by score desc limit 2
) 
union all (
  select * from users 
  where id in (select id from users where score > (select score from users u where u.id = 5) order by score ASC)
  order by score ASC limit 2
) 
order by score

Answer 5

Perhaps using union all

(
 select * from users where id < 5 order by score limit 2
)
union all
(
  select * from users where id > 5 order by score limit 2
)