I know the start date start
and the last date maturity
. How can I fill in a vector with dates without taking weekends dates into account ?
For ins
This less human than @joran answer:) , but it is no local-time depending
dd <- seq(as.Date('2011-01-01'),as.Date('2011-12-31'),by = 1)
dd[! (as.POSIXlt(dd)$wd %in% c(0,1))]
PS : another option , is to set locals before applying weekdays
tt <- Sys.getlocale('LC_TIME')
Sys.setlocale('LC_TIME','ENGLISH')
dd <- dd[!weekdays(x) %in% c('Saturday','Sunday')]
Sys.setlocale('LC_TIME',tt)
There are probably a billion ways to do this with a variety of functions from multiple packages. But my first thought is to simply make a sequence and then remove the weekends:
x <- seq(as.Date('2011-01-01'),as.Date('2011-12-31'),by = 1)
x <- x[!weekdays(x) %in% c('Saturday','Sunday')]
This answer is valid only with an English based system. For instance, in a French version, 'Saturday' and 'Sunday' must be translated into 'samedi' and 'dimanche'