sum list of dictionary values

Question

I have a list of dictionary in this form :

[
{\'signal_8\': 1, \'signal_1\': 7, \'signal_10\': 5, \'signal_5\': 2, \'signal_2\': 5, \'signal_6\': 3, \'signa         


        

Answer 1

Try this:

original_list = [
{'signal_8': 1, 'signal_1': 7, 'signal_10': 5, 'signal_5': 2, 'signal_2': 5, 'signal_6': 3, 'signal_4': 9, 'signal_3': 6, 'signal_9': 4, 'signal_7': 8}, 

{'signal_8': 1, 'signal_1': 7, 'signal_10': 5, 'signal_5': 2, 'signal_2': 5, 'signal_6': 3, 'signal_4': 9, 'signal_3': 6, 'signal_9': 4, 'signal_7': 8},

{'signal_8': 1, 'signal_1': 7, 'signal_10': 5, 'signal_5': 2, 'signal_2': 5, 'signal_6': 3, 'signal_4': 9, 'signal_3': 6, 'signal_9': 4, 'signal_7': 8},
]
print({k:sum([x[k] for x in original_list if k in x]) for i in original_list for k,v in i.items()})

Output:

{'signal_8': 3, 'signal_1': 21, 'signal_10': 15, 'signal_5': 6, 'signal_2': 15, 'signal_6': 9, 'signal_4': 27, 'signal_3': 18, 'signal_9': 12, 'signal_7': 24}

Note that if there are missing signals, it will just consider it as zero