Launch Skype from Android App programmatically

Question

I create a call directly using the default os dialer by:

Intent call = new Intent(Intent.ACTION_CALL);
call.setData(Uri.parse(\"tel:\" + phoneNo));
startActi         


        

Answer 1

You need to know Skype package name (something like: com.skype.android), then you can start it:

PackageManager packageManager = getPackageManager();
startActivity(packageManager.getLaunchIntentForPackage("com.skype.android"));

Answer 2

In your case there may be bellow case happen:

1. Skype not installed
2. Skype is disabled
3. Skype is installed

For case 1 and 2 you won't able to call skype. For case 3 you can call via skype. Please check the bellow cases for start skype:

String appName = "Skype";
String packageName = "com.skype.raider";
openApp(context, appName, packageName);

public static void openApp(Context context, String appName, String packageName) {
    if (isAppInstalled(context, packageName))
        if (isAppEnabled(context, packageName))
            context.startActivity(context.getPackageManager().getLaunchIntentForPackage(packageName));
        else Toast.makeText(context, appName + " app is not enabled.", Toast.LENGTH_SHORT).show();
    else Toast.makeText(context, appName + " app is not installed.", Toast.LENGTH_SHORT).show();
}

Check is app installed or not :

private static boolean isAppInstalled(Context context, String packageName) {
        PackageManager pm = context.getPackageManager();
        try {
            pm.getPackageInfo(packageName, PackageManager.GET_ACTIVITIES);
            return true;
        } catch (PackageManager.NameNotFoundException ignored) {
        }
        return false;
    }

Check is app enabled or not :

private static boolean isAppEnabled(Context context, String packageName) {
        boolean appStatus = false;
        try {
            ApplicationInfo ai = context.getPackageManager().getApplicationInfo(packageName, 0);
            if (ai != null) {
                appStatus = ai.enabled;
            }
        } catch (PackageManager.NameNotFoundException e) {
            e.printStackTrace();
        }
        return appStatus;
    }