Looping seems to not follow sequence

Question

I feel like I\'m missing something obvious here!

seq = {\'a\': [\'1\'], \'aa\': [\'2\'], \'aaa\': [\'3\'], \'aaaa\': [\'4\'], \'aaaaa\': [\'5\']}
for s in seq         


        

Answer 1

why you don't do (dictionary are not ordered):

for s in range(5):
    print 'a'*s

Edit : ok as you which :)

the thing is in the expression : 'a'*s which mean create a new string which contain s time 'a'.

in the python interpreter you can play with it (isn't python wonderful :) )

>>> print 'a'*2
aa
>>> print 'a'*3
aaa 

PS: if you're new to python i will suggest that you use ipython if you don't use it yet.

Answer 2

Dictionaries are not ordered. If you need to rely on the ordering, you need an OrderedDict - there's one in the collections module in Python 2.7, or you can use one of the many recipes around.

Answer 3

Standard Python dictionaries are not ordered: there is no guarantee on which order the keys will be returned.

If you want your keys returned in the order in which you create keys you can use an OrderedDict from collections.

Alternatively, if you want your output sorted on the values of the keys the following would do:

for s in sorted(seq):
    print s