Python Format Decimal with a minimum number of Decimal Places

Question

I have some Decimal instances in Python. I wish to format them such that

Decimal(\'1\')       => \'1.00\'
Decimal(\'12.0\')    => \'12.00         


        

Answer 1

If you wish to avoid string issues:

if d*100 - int(d*100):
    print str(d)
else:
    print ".2f" % d

Untested code, but it should work.

This works like so:

d = 12.345

Times 100:

1234.5

Minus int(1234.5)

1234.5 - 1234 = .5

.5 != 0

This means that there are 3 or more decimal places.

print str(12.345)

Even if you do 12.3405:

1234.05 - 1234 = .05

.05 != 0

But if you have 12.3:

1230 - 1230 = 0

This means to print with %.2f.