Windows temp directory details (Java)

Question

I\'m writing a program that needs a generic temp folder. I\'m trying to find details about the Windows Temp folders. There are two paths that I know about -

Answer 1

It sounds like you have two programs that need to share temp files and one definitely doesn't want spaces in the path name. Probably the easiest thing to do is:

1. set the TMP and TEMP variable to a common directory
2. launch each application (from this modified environment) - which should pick up the temp variable

So at the command prompt you could do this:

1. set TMP=c:\mytemp
2. set TEMP=c:\mytemp
3. java -cp x;y;z my.application.Entry
4. run other application (hopefully it also reads the environment for temp/tmp)

Hope that helps.

Answer 2

you can try this way

System.out.println(File.createTempFile("temp-file", "tmp").getParent());
String property = "java.io.tmpdir";
String tempDir = System.getProperty(property);
System.out.println("OS current temporary directory is " + tempDir);

Answer 3

This will give you the path to the windows temp directory in Java.

File.createTempFile("temp-file", "tmp").getParent()

Answer 4

To answer part of your question - if you're using .NET, you can use the Path.GetTempPath() method of the System.IO namespace to get the location of the temporary directory.

// Get the path of the temporary directory
string tempDir = Path.GetTempPath();

// "Creates a uniquely named, zero-byte temporary file on disk and returns the full path of that file."
string tempFile = Path.GetTempFileName();

Answer 5

The %TEMP% environment variable that's defined on my PC (XP SP3) uses the DOS-style abcdef~1 directory names - hence, if you can pull that variable, you should end up with a path without spaces.

e.g. Start>Run>%TEMP% takes me to C:\DOCUME~1\<user>\LOCALS~1\Temp

However, if a 'super-user' fiddles around with that variable and points it somewhere else, it's possible that things will fall over. You could look at something like this to retrieve the 8-char-and-no-spaces path.

Answer 6

use this code

   try {    String s=File.createTempFile("temp-file", "tmp").getParent();
            System.out.println(s);

        } catch (IOException ex) {
            Logger. getLogger(Result.class.getName()).log(Level.SEVERE, null, ex);
            }